(x+3)(x^2-2x+4)=0

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Solution for (x+3)(x^2-2x+4)=0 equation: 


Simplifying
(x + 3)(x2 + -2x + 4) = 0

Reorder the terms:
(3 + x)(x2 + -2x + 4) = 0

Reorder the terms:
(3 + x)(4 + -2x + x2) = 0

Multiply (3 + x) * (4 + -2x + x2)
(3(4 + -2x + x2) + x(4 + -2x + x2)) = 0
((4 * 3 + -2x * 3 + x2 * 3) + x(4 + -2x + x2)) = 0
((12 + -6x + 3x2) + x(4 + -2x + x2)) = 0
(12 + -6x + 3x2 + (4 * x + -2x * x + x2 * x)) = 0
(12 + -6x + 3x2 + (4x + -2x2 + x3)) = 0

Reorder the terms:
(12 + -6x + 4x + 3x2 + -2x2 + x3) = 0

Combine like terms: -6x + 4x = -2x
(12 + -2x + 3x2 + -2x2 + x3) = 0

Combine like terms: 3x2 + -2x2 = 1x2
(12 + -2x + 1x2 + x3) = 0

Solving
12 + -2x + 1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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